C Program to Display Numbers From 1 to n Except 6 and 9

Introduction

In this article, we will explore various approaches to a c program to display numbers from 1 to n except 6 and 9.

We will delve into different strategies for implementation, allowing you to choose the one that best suits your needs. So, let’s dive in!

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In the realm of programming, the language C is known for its versatility and extensive capabilities.

When it comes to the task of displaying numbers within a specific range, programmers often encounter the need to exclude certain digits.

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C Program to Display Numbers From 1 to n Except 6 and 9

To begin, let’s examine a few alternative approaches for a C program that displays numbers from 1 to a given value, while excluding the digits 6 and 9.

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Below are three different implementations to achieve this:

Approach 1: Conditional Statements

#include <stdio.h>

void displayNumbers(int n) {
    int i;
    for (i = 1; i <= n; i++) {
        if (i != 6 && i != 9) {
            printf("%d ", i);
        }
    }
}

int main() {
    int n;
    printf("Enter the value of n: ");
    scanf("%d", &n);
    printf("Numbers from 1 to %d except 6 and 9 are: ", n);
    displayNumbers(n);
    return 0;
}

This approach employs conditional statements within a for loop to iterate from 1 to the given value of n.

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By checking if the current number is equal to 6 or 9, and only printing it if it does not match either of these values, we can exclude the desired digits from the output.

Approach 2: Ternary Operator

#include <stdio.h>

void displayNumbers(int n) {
    int i;
    for (i = 1; i <= n; i++) {
        (i != 6 && i != 9) ? printf("%d ", i) : 0;
    }
}

int main() {
    int n;
    printf("Enter the value of n: ");
    scanf("%d", &n);
    printf("Numbers from 1 to %d except 6 and 9 are: ", n);
    displayNumbers(n);
    return 0;
}

In this approach, we utilize the ternary operator (? :) as a concise alternative to the if-else statement.

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The program checks if the current number is equal to 6 or 9. If it is not, the number is printed; otherwise, it evaluates to 0 and is skipped.

Approach 3: Bitwise Operations

#include <stdio.h>

void displayNumbers(int n) {
    int i;
    for (i = 1; i <= n; i++) {
        if ((i & 6) && (i & 9)) {
            printf("%d ", i);
        }
    }
}

int main() {
    int n;
    printf("Enter the value of n: ");
    scanf("%d", &n);
    printf("Numbers from 1 to %d except 6 and 9 are: ", n);
    displayNumbers(n);
    return 0;
}

This approach leverages bitwise operations to check if the bits representing 6 and 9 are set in the binary representation of the current number.

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If neither of these bits is set, the number is printed.

Implementation Details

Now that we have explored multiple approaches, let’s delve into their implementation details. Each approach utilizes a for loop to iterate from 1 to the given value of n.

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Inside the loop, the program employs different techniques to exclude the digits 6 and 9 from the output.

In the first approach, conditional statements are used to check if the current number is equal to 6 or 9. If not, the number is printed.

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The second approach employs the ternary operator as a shorthand way of achieving the same result.

The third approach utilizes bitwise operations to check if the bits representing 6 and 9 are set, effectively excluding numbers with those bits set from the output.

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FAQs about C Program to Display Numbers From 1 to n Except 6 and 9

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Conclusion

In conclusion, we have explored different approaches to a C program to display numbers from 1 to n except 6 and 9.

Each approach offers its own unique implementation using conditional statements, ternary operators, or bitwise operations.

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By choosing the approach that aligns with your coding style and requirements, you can achieve the desired output efficiently.

Feel free to modify the programs and experiment further. Happy coding!